请在这里概述您的问题(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时是多少(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时,得多少
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![请在这里概述您的问题(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时是多少(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时,得多少](/uploads/image/z/4663000-64-0.jpg?t=%E8%AF%B7%E5%9C%A8%E8%BF%99%E9%87%8C%E6%A6%82%E8%BF%B0%E6%82%A8%E7%9A%84%E9%97%AE%E9%A2%98%28x%26%23178%3B-2x%29%2F%282y-xy%29%3Dx%28x-2%29%2F%5By%282-x%29%5D%3D-x%28x-2%29%2F%5By%28x-2%29%5D%3D-x%2Fy.%E5%BD%93X%3D-1%2CY%3D2%E6%97%B6%E6%98%AF%E5%A4%9A%E5%B0%91%28x%26%23178%3B-2x%29%2F%282y-xy%29%3Dx%28x-2%29%2F%5By%282-x%29%5D%3D-x%28x-2%29%2F%5By%28x-2%29%5D%3D-x%2Fy.%E5%BD%93X%3D-1%2CY%3D2%E6%97%B6%2C%E5%BE%97%E5%A4%9A%E5%B0%91)
请在这里概述您的问题(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时是多少(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时,得多少
请在这里概述您的问题(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时是多少
(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时,得多少
请在这里概述您的问题(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时是多少(x²-2x)/(2y-xy)=x(x-2)/[y(2-x)]=-x(x-2)/[y(x-2)]=-x/y.当X=-1,Y=2时,得多少
解
代入就行啦
原式=-x/y=-(-1)/2=1/2