1.若α+β=45°,求证(tanα+1)(tanβ+1)=2 2.若(tanα+1)(tanβ+1)=2,求α+β的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/25 18:53:31
![1.若α+β=45°,求证(tanα+1)(tanβ+1)=2 2.若(tanα+1)(tanβ+1)=2,求α+β的值](/uploads/image/z/5189917-13-7.jpg?t=1.%E8%8B%A5%CE%B1%2B%CE%B2%3D45%C2%B0%2C%E6%B1%82%E8%AF%81%EF%BC%88tan%CE%B1%2B1%29%28tan%CE%B2%2B1%EF%BC%89%3D2+2.%E8%8B%A5%EF%BC%88tan%CE%B1%2B1%EF%BC%89%EF%BC%88tan%CE%B2%2B1%EF%BC%89%3D2%2C%E6%B1%82%CE%B1%2B%CE%B2%E7%9A%84%E5%80%BC)
1.若α+β=45°,求证(tanα+1)(tanβ+1)=2 2.若(tanα+1)(tanβ+1)=2,求α+β的值
1.若α+β=45°,求证(tanα+1)(tanβ+1)=2 2.若(tanα+1)(tanβ+1)=2,求α+β的值
1.若α+β=45°,求证(tanα+1)(tanβ+1)=2 2.若(tanα+1)(tanβ+1)=2,求α+β的值
(Tana+1)(tanb+1)=tanatanb+tana+tanb+1=tanatanb+tan(a+b)(1-tanatanb)+1(a+b=45,tan(a+b)=1)=2.(tana+1)(tanb+1)=2_tanatanb+tana+tanb+1=2._tanatanb+tan(a+b)(1-tanatanb)=1.故tan(a+b)=1.a+b=45.