f(x)在[0,1]上连续,在(0,1)上可导,且f(1)=0,则存在0
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![f(x)在[0,1]上连续,在(0,1)上可导,且f(1)=0,则存在0](/uploads/image/z/5231078-62-8.jpg?t=f%28x%29%E5%9C%A8%5B0%2C1%5D%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%E5%9C%A8%280%2C1%29%E4%B8%8A%E5%8F%AF%E5%AF%BC%2C%E4%B8%94f%281%29%3D0%2C%E5%88%99%E5%AD%98%E5%9C%A80)
f(x)在[0,1]上连续,在(0,1)上可导,且f(1)=0,则存在0
f(x)在[0,1]上连续,在(0,1)上可导,且f(1)=0,则存在0
f(x)在[0,1]上连续,在(0,1)上可导,且f(1)=0,则存在0
设F(x)=x^nf(x),F(1)=0,F(0)=0,F(x)在区间[0,1]满足罗尔定理的条件,由罗尔定理,存在t,0
证明什么
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