1.已知:5x^2-4xy+y^2-2x+1=0,则(x-y)^2005+__________.
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![1.已知:5x^2-4xy+y^2-2x+1=0,则(x-y)^2005+__________.](/uploads/image/z/5242229-53-9.jpg?t=1.%E5%B7%B2%E7%9F%A5%3A5x%5E2-4xy%2By%5E2-2x%2B1%3D0%2C%E5%88%99%28x-y%29%5E2005%2B__________.)
1.已知:5x^2-4xy+y^2-2x+1=0,则(x-y)^2005+__________.
1.已知:5x^2-4xy+y^2-2x+1=0,则(x-y)^2005+__________.
1.已知:5x^2-4xy+y^2-2x+1=0,则(x-y)^2005+__________.
(4x^2-4xy+y^2)+(x^2-2x+1)=0
=>(2x-y)^2+(x-1)^2=0
x=1
y=2
(x-y)^2005=-1
4x^2-4xy+y^2+x^2-2x+1=(2X-Y)^2+(X-1)^2=0
(2X-Y)^2=0 (X-1)^2=0
X=2Y X=1
带入 为-1