(x-1)²=(2x+3)²
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![(x-1)²=(2x+3)²](/uploads/image/z/5246759-47-9.jpg?t=%EF%BC%88x-1%29%26%23178%3B%3D%EF%BC%882x%2B3%EF%BC%89%26%23178%3B)
(x-1)²=(2x+3)²
(x-1)²=(2x+3)²
(x-1)²=(2x+3)²
(x-1)²=(2x+3)²
所以x-1=2x+3,或x-1=-(2x+3)
所以x=-4,或x=-2/3
望采纳
(x-1)²=(2x+3)²
(x-1)²-(2x+3)²=0
[(x-1)+(2x+3)][(x-1)-(2x+3)]=0
(3x+2)(-x-4)=0
x1=-2/3, x2=-4