如果m,n满足|m+2|+(n-4)²=0,那么你能将代数式(x²+y²)-(mxy+n)分解因式吗?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/25 02:49:57
![如果m,n满足|m+2|+(n-4)²=0,那么你能将代数式(x²+y²)-(mxy+n)分解因式吗?](/uploads/image/z/5468453-53-3.jpg?t=%E5%A6%82%E6%9E%9Cm%2Cn%E6%BB%A1%E8%B6%B3%EF%BD%9Cm%2B2%EF%BD%9C%2B%EF%BC%88n-4%EF%BC%89%26%23178%3B%3D0%2C%E9%82%A3%E4%B9%88%E4%BD%A0%E8%83%BD%E5%B0%86%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%BC%88x%26%23178%3B%2By%26%23178%3B%EF%BC%89-%EF%BC%88mxy%2Bn%29%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%E5%90%97%3F)
如果m,n满足|m+2|+(n-4)²=0,那么你能将代数式(x²+y²)-(mxy+n)分解因式吗?
如果m,n满足|m+2|+(n-4)²=0,那么你能将代数式(x²+y²)-(mxy+n)分解因式吗?
如果m,n满足|m+2|+(n-4)²=0,那么你能将代数式(x²+y²)-(mxy+n)分解因式吗?
|m+2|+(n-4)²=0
得{m+2=0
n-4=0
即{m=-2,n=4
(x²+y²)-(mxy+n)
=(x²+y²)-(-2xy+4)
=x^2+y^2+2xy-4
=(x+y)^2-4
=(x+y+2)(x+y-2)