(x^2-1)\(x^2-4x+a)除以(x+1)x(x^2-3x+2)\(x-1)
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![(x^2-1)\(x^2-4x+a)除以(x+1)x(x^2-3x+2)\(x-1)](/uploads/image/z/582519-39-9.jpg?t=%28x%5E2-1%29%5C%28x%5E2-4x%2Ba%EF%BC%89%E9%99%A4%E4%BB%A5%EF%BC%88x%2B1%EF%BC%89x%EF%BC%88x%5E2-3x%2B2%EF%BC%89%5C%EF%BC%88x-1%EF%BC%89)
(x^2-1)\(x^2-4x+a)除以(x+1)x(x^2-3x+2)\(x-1)
(x^2-1)\(x^2-4x+a)除以(x+1)x(x^2-3x+2)\(x-1)
(x^2-1)\(x^2-4x+a)除以(x+1)x(x^2-3x+2)\(x-1)
a错了,是4
原式=(x+1)(x-1)/(x-2)²*1/(x+1)*(x-1)(x-2)/(x-1)
=(x-1)/(x-2)²*(x-2)
=(x-1)/(x-2)
楼上正解
3