(2x+5y)²= (-2t-1)²= (3x-2y+1)²= 添括号:x-3x²y-4x³+1=x-(2x+y)²-(2x-y)² (3x-5)²(3x+5)² 已知x²+2x+y²-6y+10=0,则x=,y=
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 06:18:14
![(2x+5y)²= (-2t-1)²= (3x-2y+1)²= 添括号:x-3x²y-4x³+1=x-(2x+y)²-(2x-y)² (3x-5)²(3x+5)² 已知x²+2x+y²-6y+10=0,则x=,y=](/uploads/image/z/584629-61-9.jpg?t=%282x%2B5y%29%26%23178%3B%3D+%EF%BC%88-2t-1%EF%BC%89%26%23178%3B%3D+%EF%BC%883x-2y%2B1%EF%BC%89%26%23178%3B%3D+%E6%B7%BB%E6%8B%AC%E5%8F%B7%EF%BC%9Ax-3x%26%23178%3By-4x%26%23179%3B%2B1%3Dx-%282x%2By%29%26%23178%3B-%EF%BC%882x-y%EF%BC%89%26%23178%3B+%EF%BC%883x-5%EF%BC%89%26%23178%3B%EF%BC%883x%2B5%EF%BC%89%26%23178%3B+%E5%B7%B2%E7%9F%A5x%26%23178%3B%2B2x%2By%26%23178%3B-6y%2B10%3D0%2C%E5%88%99x%3D%2Cy%3D)
(2x+5y)²= (-2t-1)²= (3x-2y+1)²= 添括号:x-3x²y-4x³+1=x-(2x+y)²-(2x-y)² (3x-5)²(3x+5)² 已知x²+2x+y²-6y+10=0,则x=,y=
(2x+5y)²= (-2t-1)²= (3x-2y+1)²= 添括号:x-3x²y-4x³+1=x-
(2x+y)²-(2x-y)²
(3x-5)²(3x+5)²
已知x²+2x+y²-6y+10=0,则x=,y=
(2x+5y)²= (-2t-1)²= (3x-2y+1)²= 添括号:x-3x²y-4x³+1=x-(2x+y)²-(2x-y)² (3x-5)²(3x+5)² 已知x²+2x+y²-6y+10=0,则x=,y=
根据已知,(x+1)^2+(y-3)^2=0
即,x=-1 y=3 (有问题再一起讨论哟!)