1)4x^2+4xy-3y^2+4x+10y-32)x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 19:15:42
1)4x^2+4xy-3y^2+4x+10y-32)x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2

1)4x^2+4xy-3y^2+4x+10y-32)x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2
1)4x^2+4xy-3y^2+4x+10y-3
2)x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2

1)4x^2+4xy-3y^2+4x+10y-32)x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2
(1)4x^2-4xy-3y^2-4x+10y-3
=(2x-3y)(2x+y)+(2x+y)-6x+9y-3
=(2x+y)(2x-3y+1)-3(2x-3y+1)
=(2x-3y+1)(2x+y-3)
(2)原式==(x^2+y^2-z^2)^2-(2xy)^2
=(x^2+y^2-z^2+2xy)(x^2+y^2-z^2-2xy)
=[(x+y)^2-z^2][(x-y)^2-z^2]
=(x+y+z)(x+y-z)(x-y+z)(x-y-z)

1)
4x^2-4xy-3y^2-4x+10y-3
=(2x-3y)(2x+y)+(2x+y)-6x+9y-3
=(2x+y)(2x-3y+1)-3(2x-3y+1)
=(2x-3y+1)(2x+y-3)

2)原式=
x^4-(2y^2+2z^2)x^2+y^4+z^4-2y^2z^2
=x^4-(2y^2+2z^2)x^2+(y^2-z^2)^2
=x^4-(2y^2+2z^2)x^2+(y+z)^2(y-z)^2
=[x^2-(y+z)^2][x^2-(y-z)^2]
=(x+y+z)(x-y-z)(x+y-z)(x-y+z)