a b满足a(a+1)-(a²+2b)=1求a²-4ab+4b²-2a+4b
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![a b满足a(a+1)-(a²+2b)=1求a²-4ab+4b²-2a+4b](/uploads/image/z/603319-31-9.jpg?t=a+b%E6%BB%A1%E8%B6%B3a%EF%BC%88a%EF%BC%8B1%EF%BC%89-%28a%26%23178%3B%EF%BC%8B2b%EF%BC%89%3D1%E6%B1%82a%26%23178%3B-4ab%EF%BC%8B4b%26%23178%3B-2a%EF%BC%8B4b)
a b满足a(a+1)-(a²+2b)=1求a²-4ab+4b²-2a+4b
a b满足a(a+1)-(a²+2b)=1求a²-4ab+4b²-2a+4b
a b满足a(a+1)-(a²+2b)=1求a²-4ab+4b²-2a+4b
a(a+1)-(a²+2b)=1
a²+a-a²-2b=1
a-2b=1
a²-4ab+4b²-2a+4b
=(a-2b)²-2(a-2b)
=1-2
=-1