用提公因式法把下列各式化简1 p(a²+b²)-q(a²+b²) 24q(1-p)³+2(p-1)² 3 (a-3)²-(6-2a)简便计算101²-101已知a+b=10,ab=24,求2(a²b+ab²)+4(a+b)的值
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![用提公因式法把下列各式化简1 p(a²+b²)-q(a²+b²) 24q(1-p)³+2(p-1)² 3 (a-3)²-(6-2a)简便计算101²-101已知a+b=10,ab=24,求2(a²b+ab²)+4(a+b)的值](/uploads/image/z/62520-24-0.jpg?t=%E7%94%A8%E6%8F%90%E5%85%AC%E5%9B%A0%E5%BC%8F%E6%B3%95%E6%8A%8A%E4%B8%8B%E5%88%97%E5%90%84%E5%BC%8F%E5%8C%96%E7%AE%801+p%EF%BC%88a%26%23178%3B%2Bb%26%23178%3B%EF%BC%89-q%28a%26%23178%3B%2Bb%26%23178%3B%EF%BC%89+24q%EF%BC%881-p%EF%BC%89%26%23179%3B%2B2%EF%BC%88p-1%EF%BC%89%26%23178%3B+3+%EF%BC%88a-3%EF%BC%89%26%23178%3B-%EF%BC%886-2a%EF%BC%89%E7%AE%80%E4%BE%BF%E8%AE%A1%E7%AE%97101%26%23178%3B-101%E5%B7%B2%E7%9F%A5a%2Bb%3D10%EF%BC%8Cab%3D24%EF%BC%8C%E6%B1%822%EF%BC%88a%26%23178%3Bb%2Bab%26%23178%3B%EF%BC%89%2B4%EF%BC%88a%2Bb%EF%BC%89%E7%9A%84%E5%80%BC)
用提公因式法把下列各式化简1 p(a²+b²)-q(a²+b²) 24q(1-p)³+2(p-1)² 3 (a-3)²-(6-2a)简便计算101²-101已知a+b=10,ab=24,求2(a²b+ab²)+4(a+b)的值
用提公因式法把下列各式化简
1
p(a²+b²)-q(a²+b²)
2
4q(1-p)³+2(p-1)²
3
(a-3)²-(6-2a)
简便计算101²-101
已知a+b=10,ab=24,求2(a²b+ab²)+4(a+b)的值
用提公因式法把下列各式化简1 p(a²+b²)-q(a²+b²) 24q(1-p)³+2(p-1)² 3 (a-3)²-(6-2a)简便计算101²-101已知a+b=10,ab=24,求2(a²b+ab²)+4(a+b)的值
1.(a^2+b^2)(p-q)
2.(1-p)^2(4q-4pq+2)
3.(a-3)(a-3+2)=(a-3)(a-1)
4.101^2-101=101*(101-1)=10100
5.2(a^2b+ab^2)+4(a+b)
=2ab(a+b)+4(a+b)
=(a+b)(2ab+4)
=10*52=520
1
p(a²+b²)-q(a²+b²)
=(p-q) (a²+b²)
2
4q(1-p)³+2(p-1)²
=(4q-4pq+2) (p-1)²
3
(a-3)²-(6-2a)
=(a-3)²+2(a...
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1
p(a²+b²)-q(a²+b²)
=(p-q) (a²+b²)
2
4q(1-p)³+2(p-1)²
=(4q-4pq+2) (p-1)²
3
(a-3)²-(6-2a)
=(a-3)²+2(a-3)
=(a-3)(a-3+2)
=(a-3)(a-1)
收起
1 提公因子(a²+b²)(P-q)
2先提公因子(p-1)² (1+2pq-2q)
3 括号先展开,再十字相乘 (a-1)(a-3)