设a,B属于[0,兀/2],f(3a+兀/2)=10/13,f(3B+2兀)=6/5 求sin(a

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设a,B属于[0,兀/2],f(3a+兀/2)=10/13,f(3B+2兀)=6/5 求sin(a

设a,B属于[0,兀/2],f(3a+兀/2)=10/13,f(3B+2兀)=6/5 求sin(a
设a,B属于[0,兀/2],f(3a+兀/2)=10/13,f(3B+2兀)=6/5 求sin(a

设a,B属于[0,兀/2],f(3a+兀/2)=10/13,f(3B+2兀)=6/5 求sin(a
lz你确定你的题没错?