a+b/a-b=b+c/2(b-c)=c+a/3(c-a)=k,a,b,c互不相等,求8a+9b+5c的值
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![a+b/a-b=b+c/2(b-c)=c+a/3(c-a)=k,a,b,c互不相等,求8a+9b+5c的值](/uploads/image/z/6372039-39-9.jpg?t=a%2Bb%2Fa-b%3Db%2Bc%2F2%28b-c%29%3Dc%2Ba%2F3%28c-a%29%3Dk%2Ca%2Cb%2Cc%E4%BA%92%E4%B8%8D%E7%9B%B8%E7%AD%89%2C%E6%B1%828a%2B9b%2B5c%E7%9A%84%E5%80%BC)
a+b/a-b=b+c/2(b-c)=c+a/3(c-a)=k,a,b,c互不相等,求8a+9b+5c的值
a+b/a-b=b+c/2(b-c)=c+a/3(c-a)=k,a,b,c互不相等,求8a+9b+5c的值
a+b/a-b=b+c/2(b-c)=c+a/3(c-a)=k,a,b,c互不相等,求8a+9b+5c的值
设(a+b)/(a-b)=(b+c)/[2(b-c)]=(c+a)/[3(c-a)]=k
则 a+b=k(a-b) (1)
(b+c)/2=k(b-c) (2)
(a+c)/3=k(c-a) (3)
(1)+(2)+(3):a+b+b/2+c/2+a/3+c/3=0 (4)
(4)两边同乘6:6a+6b+3b+3c+2a+2c=0
即:8a+9b+5c=0
题目是不是打错了。。。