如图,∠BAC=90°,AC=DC,M为BC中点,MN‖AD,交AC于N,求证DN=1/2BC.
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 05:36:24
![如图,∠BAC=90°,AC=DC,M为BC中点,MN‖AD,交AC于N,求证DN=1/2BC.](/uploads/image/z/6645826-10-6.jpg?t=%E5%A6%82%E5%9B%BE%2C%E2%88%A0BAC%3D90%C2%B0%2CAC%3DDC%2CM%E4%B8%BABC%E4%B8%AD%E7%82%B9%2CMN%E2%80%96AD%2C%E4%BA%A4AC%E4%BA%8EN%2C%E6%B1%82%E8%AF%81DN%3D1%2F2BC.)
如图,∠BAC=90°,AC=DC,M为BC中点,MN‖AD,交AC于N,求证DN=1/2BC.
如图,∠BAC=90°,AC=DC,M为BC中点,MN‖AD,交AC于N,求证DN=1/2BC.
如图,∠BAC=90°,AC=DC,M为BC中点,MN‖AD,交AC于N,求证DN=1/2BC.
连AM,由M是斜边BC中点,∴AM=(1/2)BC.
∵AC=DC,MN∥AD,
∴四边形ADMN是等腰梯形,对角线AM=DN,
∴DN=(1/2)BC.