f(x)=根号1+x,化简f(sin2)-f(-sin2)=
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f(x)=根号1+x,化简f(sin2)-f(-sin2)=
f(x)=根号1+x,化简f(sin2)-f(-sin2)=
f(x)=根号1+x,化简f(sin2)-f(-sin2)=
原式=√(1+sin2)+√(1-sin2)
1+sin2
=sin²1+cos²1+2sin1cos1
=(sin1+cos1)²
同理1-sin=(sin1-cos1)²
π与等于3.14
所以π/40
所以原式=|sin1+cos1|+|sin1-cos1|
=sin1+cos1+sin1-cos1
=2sin1