三元一次方程组 公式 c语言#include #include #include main(){double a,b,c,d,A,B,C,D,e,f,g,h,x,y,z;scanf("%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf",&a,&b,&c,&d,&A,&B,&C,&D,&e,&f,&g,&h);x=(d-(b*y)-(c*z))/a; (此处可能有误!)y=(D-((d-(b*y)-
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![三元一次方程组 公式 c语言#include #include #include main(){double a,b,c,d,A,B,C,D,e,f,g,h,x,y,z;scanf(](/uploads/image/z/6872823-63-3.jpg?t=%E4%B8%89%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%E7%BB%84+%E5%85%AC%E5%BC%8F+c%E8%AF%AD%E8%A8%80%23include+%23include+%23include+main%28%29%7Bdouble+a%2Cb%2Cc%2Cd%2CA%2CB%2CC%2CD%2Ce%2Cf%2Cg%2Ch%2Cx%2Cy%2Cz%3Bscanf%28%22%25lf%25lf%25lf%25lf%25lf%25lf%25lf%25lf%25lf%25lf%25lf%25lf%22%2C%26a%2C%26b%2C%26c%2C%26d%2C%26A%2C%26B%2C%26C%2C%26D%2C%26e%2C%26f%2C%26g%2C%26h%29%3Bx%3D%28d-%28b%2Ay%29-%28c%2Az%29%29%2Fa%3B+%EF%BC%88%E6%AD%A4%E5%A4%84%E5%8F%AF%E8%83%BD%E6%9C%89%E8%AF%AF%21%EF%BC%89y%3D%28D-%28%28d-%28b%2Ay%29-)
三元一次方程组 公式 c语言#include #include #include main(){double a,b,c,d,A,B,C,D,e,f,g,h,x,y,z;scanf("%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf",&a,&b,&c,&d,&A,&B,&C,&D,&e,&f,&g,&h);x=(d-(b*y)-(c*z))/a; (此处可能有误!)y=(D-((d-(b*y)-
三元一次方程组 公式 c语言
#include
#include
#include
main()
{
double a,b,c,d,A,B,C,D,e,f,g,h,x,y,z;
scanf("%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf",&a,&b,&c,&d,&A,&B,&C,&D,&e,&f,&g,&h);
x=(d-(b*y)-(c*z))/a; (此处可能有误!)
y=(D-((d-(b*y)-(c*z))/a*A)-(C*z))/B; (此处可能有误!)
z=(h-((d-(b*y)-(c*z))/a)*e-(f*(D-((d-(b*y)-(c*z))/a*A)-(C*z))/B))/g;(此处可能有误!)
printf("%lf\n%lf\n%lf",x,y,z);
}
方程组:{a*x+b*y+c*z=d
{A*x+B*y+C*z=D
{e*x+f*y+g*z=h
只用说出化简后的公式
化简成x=...y=...z=...的形式,
三元一次方程组 公式 c语言#include #include #include main(){double a,b,c,d,A,B,C,D,e,f,g,h,x,y,z;scanf("%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf",&a,&b,&c,&d,&A,&B,&C,&D,&e,&f,&g,&h);x=(d-(b*y)-(c*z))/a; (此处可能有误!)y=(D-((d-(b*y)-
赋值表达式的右值必须确定才能进行赋值,你把X,Y,Z的方程化简一下,让表达式的右边没有未知数.