如果a,b满足(a²+b²)(a²+b²-6)=-9 试求a²+b²的值
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如果a,b满足(a²+b²)(a²+b²-6)=-9 试求a²+b²的值
如果a,b满足(a²+b²)(a²+b²-6)=-9 试求a²+b²的值
如果a,b满足(a²+b²)(a²+b²-6)=-9 试求a²+b²的值
(a²+b²)(a²+b²-6)=-9
(a²+b²)²-6(a²+b²)+9=0
(a²+b²-3)²=0
a²+b²-3=0
a²+b²=3
加油!
设(a²+b²)为x
原式
x(x-6)+9=0
x^2-6x+9=0
(x-3)^2=0
x=3
所以
a²+b²=3