a,b均为实数,且满足(3a+b)²+|a²-25|/√4-a=0,那么b=__________
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![a,b均为实数,且满足(3a+b)²+|a²-25|/√4-a=0,那么b=__________](/uploads/image/z/6952956-60-6.jpg?t=a%2Cb%E5%9D%87%E4%B8%BA%E5%AE%9E%E6%95%B0%2C%E4%B8%94%E6%BB%A1%E8%B6%B3%283a%2Bb%29%26%23178%3B%2B%7Ca%26%23178%3B-25%7C%2F%E2%88%9A4-a%3D0%2C%E9%82%A3%E4%B9%88b%3D__________)
a,b均为实数,且满足(3a+b)²+|a²-25|/√4-a=0,那么b=__________
a,b均为实数,且满足(3a+b)²+|a²-25|/√4-a=0,那么b=__________
a,b均为实数,且满足(3a+b)²+|a²-25|/√4-a=0,那么b=__________
答:
a,b均为实数,且满足(3a+b)²+|a²-25|/√(4-a)=0
根据平方数和绝对值、二次根式的非负性质有:
3a+b=0
a²-25=0
4-a>0
解得:a=-5,b=15
所以:b=15
a,b均为实数,且满足(3a+b)²+|a²-25|/√4-a=0,那么b=__________
满足 3a+b = 0 a²-25 = 0 且 4-a >= 0
a = ±5 且 4-a >= 0
a = -5
b = -3a = 15
施主,我看你骨骼清奇,
器宇轩昂,且有慧根,...
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a,b均为实数,且满足(3a+b)²+|a²-25|/√4-a=0,那么b=__________
满足 3a+b = 0 a²-25 = 0 且 4-a >= 0
a = ±5 且 4-a >= 0
a = -5
b = -3a = 15
施主,我看你骨骼清奇,
器宇轩昂,且有慧根,
乃是万中无一的武林奇才.
潜心修习,将来必成大器,
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∵(3a+b)²≥0,|a²-25|/√(4-a)≥0
∴3a+b=0,a²-25=0,4-a>0
解得:a=-5,b=15