函数f(x)=Asin(2x+π/3)(A>0,x∈R)的图像过点P(7π/12,-2)1.求f(x)的解析式 2.已知f(a/2-π/6)=-10/13,(-π/2
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![函数f(x)=Asin(2x+π/3)(A>0,x∈R)的图像过点P(7π/12,-2)1.求f(x)的解析式 2.已知f(a/2-π/6)=-10/13,(-π/2](/uploads/image/z/7017687-63-7.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3DAsin%282x%2B%CF%80%2F3%29%28A%3E0%2Cx%E2%88%88R%29%E7%9A%84%E5%9B%BE%E5%83%8F%E8%BF%87%E7%82%B9P%287%CF%80%2F12%2C-2%291.%E6%B1%82f%EF%BC%88x%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F+2.%E5%B7%B2%E7%9F%A5f%EF%BC%88a%2F2-%CF%80%2F6%29%3D-10%2F13%2C%28-%CF%80%2F2)
函数f(x)=Asin(2x+π/3)(A>0,x∈R)的图像过点P(7π/12,-2)1.求f(x)的解析式 2.已知f(a/2-π/6)=-10/13,(-π/2
函数f(x)=Asin(2x+π/3)(A>0,x∈R)的图像过点P(7π/12,-2)
1.求f(x)的解析式 2.已知f(a/2-π/6)=-10/13,(-π/2
函数f(x)=Asin(2x+π/3)(A>0,x∈R)的图像过点P(7π/12,-2)1.求f(x)的解析式 2.已知f(a/2-π/6)=-10/13,(-π/2
(1)∵f(x)的图象过点P(7π/12,-2),
∴f(7π/12)=Asin(2×7π/12+π/3)=Asin(3π/2)=-2,
∴A=2,
故f(x)的解析式为f(x)=2sin(2x+π/3).
(2)∵f(a/2-π/6)=2sina=-10/13,∴sina=-5/13,
∵-π/2
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