观察下列各式(x-1)(x²+x+1)=x²-1,(x-1)(x³+x²+1)=x四次方-1根据以上算式,求出1+2+2²+·········+X六十二次方+2六十三次方的结果是
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![观察下列各式(x-1)(x²+x+1)=x²-1,(x-1)(x³+x²+1)=x四次方-1根据以上算式,求出1+2+2²+·········+X六十二次方+2六十三次方的结果是](/uploads/image/z/7172211-3-1.jpg?t=%E8%A7%82%E5%AF%9F%E4%B8%8B%E5%88%97%E5%90%84%E5%BC%8F%28x-1%29%28x%26%23178%3B%2Bx%2B1%29%3Dx%26%23178%3B-1%2C%28x-1%29%28x%26%23179%3B%2Bx%26%23178%3B%2B1%29%3Dx%E5%9B%9B%E6%AC%A1%E6%96%B9-1%E6%A0%B9%E6%8D%AE%E4%BB%A5%E4%B8%8A%E7%AE%97%E5%BC%8F%EF%BC%8C%E6%B1%82%E5%87%BA1%2B2%2B2%26%23178%3B%2B%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%2BX%E5%85%AD%E5%8D%81%E4%BA%8C%E6%AC%A1%E6%96%B9%2B2%E5%85%AD%E5%8D%81%E4%B8%89%E6%AC%A1%E6%96%B9%E7%9A%84%E7%BB%93%E6%9E%9C%E6%98%AF)
观察下列各式(x-1)(x²+x+1)=x²-1,(x-1)(x³+x²+1)=x四次方-1根据以上算式,求出1+2+2²+·········+X六十二次方+2六十三次方的结果是
观察下列各式(x-1)(x²+x+1)=x²-1,(x-1)(x³+x²+1)=x四次方-1
根据以上算式,求出1+2+2²+·········+X六十二次方+2六十三次方的结果是
观察下列各式(x-1)(x²+x+1)=x²-1,(x-1)(x³+x²+1)=x四次方-1根据以上算式,求出1+2+2²+·········+X六十二次方+2六十三次方的结果是
xⁿ - 1 = (x - 1)(xⁿ-¹ + xⁿ-² + ...+ x + 1)
题目出的不对吧?
题干应该是(x-1)(x²+x+1)=x3-1,(x-1)(x³+x²+x+1)=x4-1,
所以问题中X=2
(2-1)(1+2+2²+·········+X六十二次方+2六十三次方)=2六十四次方-1