解一元一次方程10(x+1)-5(0.2x+1)=1
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解一元一次方程10(x+1)-5(0.2x+1)=1
解一元一次方程10(x+1)-5(0.2x+1)=1
解一元一次方程10(x+1)-5(0.2x+1)=1
10x+10-x-5=1,9x=-4 所以x=-4/9
0
10(x + 1) - 5(0.2x + 1) = 1
10x + 10 - x - 5 = 5
10x - x = 5 - 10 + 5
9x = 0
x = 0
10(x+1)-5(0.2x+1)=1
10x+10-x-5=1
10x-x=1-10+5
9x=-4
x=-4/9