①x^n+1*x^n-1 ②[(x+1/2y)^2+(x-1/2y)^2](2x^2-1/2y^2) ③（a-b)^2n+2+(a-b)^2n 因式分解

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①x^n+1*x^n-1 ②[(x+1/2y)^2+(x-1/2y)^2](2x^2-1/2y^2) ③（a-b)^2n+2+(a-b)^2n 因式分解

①x^n+1*x^n-1 ②[(x+1/2y)^2+(x-1/2y)^2](2x^2-1/2y^2) ③（a-b)^2n+2+(a-b)^2n 因式分解
①x^n+1*x^n-1 ②[(x+1/2y)^2+(x-1/2y)^2](2x^2-1/2y^2) ③（a-b)^2n+2+(a-b)^2n 因式分解

①x^n+1*x^n-1 ②[(x+1/2y)^2+(x-1/2y)^2](2x^2-1/2y^2) ③（a-b)^2n+2+(a-b)^2n 因式分解
x²-2xy+y²-2x+2y+1
=(x-y)²-2(x-y)+1
=(x-y-1)²
-x^(n+1)+2x^n-x^(n-1)
=-x^(n-1)*x^2+2x^(n-1)*x-x^(n-1)
=-x^(n-1)[x^2-2x+1]
=-x^(n-1)(x-1)^2
1998×2000-1999²
=(1999-1)(1999+1)-1999²
=1999²-1-1999²
=-1
[ 三分之一(x+1)的四次方]的三次方×[-3（x+1）²]三次方
=[1/3*(x+1)^4]^3×[-3（x+1）²]^3
=1/27*(x+1)^12×[-27（x+1）^6
=-1*(x+1)^18
=-(x+1)^18

x^(n)*x^(n+1)+x^(2n)*x f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n 因式分解：(x^n+1)+(2x^n)+(x^n-1) x^n+1-2x^n+x^n-1因式分解 x^n-1-2x^n+x^n-1因式分解 若(x^2+1/x)^n(n∈N+,n 分解因式x^n-x^(n-1)+x^(n-2) x^n-2x^n+1,因式分解 x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x (-x)^3x^n-1+x^2n(-x)^3 x^n/(1+x) dx (-x)(1+x)^n求导 x（n+1） x（n+1） 求和:1+x+x^2+.+x^n (4x^n-2x^n-1-3x^n+2)÷（-5x^n-1) 计算(x^(2n)+x^n+1)(x^(3n)-x^(2n)+1) x^n-1(3x^n+4x^n+1-5x^n+2)