(2a+3b-c)(2a-3b+c)=?

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(2a+3b-c)(2a-3b+c)=?

(2a+3b-c)(2a-3b+c)=?
(2a+3b-c)(2a-3b+c)=?

(2a+3b-c)(2a-3b+c)=?
楼上的错了!
(2+1)(2-1)=2^2-1^2=3 而不是=2^2+1^2=5
所以说答案是
=4a^2-9b^2+6bc-c^2

{2a+(3b-c)][2a-(3b-c)]=4a^2+(3b-c)^2=4a^2+9b^2+c^2-6bc

(2a+3b-c)(2a-3b+c)
=(2a+(3b-c))(2a-(3b-c)
=4a^2-(3b-c)^2
=4a^2-9b^2+6bc-c^2

(2a+3b-c)(2a-3b+c)=[2a+(3b-c)]*[2a-(3b-c)]=4a*a-(3b-c)的平方=4a*a-9bb-cc+6bc

(2a+3b-c)(2a-3b+c)
=[2a+(3b-c)][2a-(3b-c)]
(2a)*2-(3b-c)*2

(2a+3b-c)(2a-3b+c)=(2a+3b-c)(2a-(3b-c))=
4a~2-9b~2+6bc-c~2
=

(2a+3b-c)(2a-3b+c)
=(2a+(3b-c))(2a-(3b-c)
=4a^2-(3b-c)^2
=4a^2-9b^2+6bc-c^2

解:(2a+3b-c)(2a-3b+c)
=[2a+(3b-c)][2a-(3b-c)]
=4a^-(3b-c)^
=4a^-(9b^-6bc+c^)
=4a^-9b^+6bc-c^