kx²-(2k+1)x=0 有三个不等式数根,怎么得到x=0或x=(2k+1)/k (x>=0)?
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kx²-(2k+1)x=0 有三个不等式数根,怎么得到x=0或x=(2k+1)/k (x>=0)?
kx²-(2k+1)x=0 有三个不等式数根,怎么得到x=0或x=(2k+1)/k (x>=0)?
kx²-(2k+1)x=0 有三个不等式数根,怎么得到x=0或x=(2k+1)/k (x>=0)?
kx²-(2k+1)x=0
x(kx-2k-1)=0
x=0或者x=(2k+1)/k