1.x^4-2=(x-y)(x+y)(x^2+y^2),当x=9.y=9时.x-y=0.x+y=18.x^2+y^2=162.则连起来为018162,对于多项式:4x^3-xy^2取x=10.y=10用上述方法可得到密码有()()()三个..2.说明任意两个连续奇数的平方差能被8整
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![1.x^4-2=(x-y)(x+y)(x^2+y^2),当x=9.y=9时.x-y=0.x+y=18.x^2+y^2=162.则连起来为018162,对于多项式:4x^3-xy^2取x=10.y=10用上述方法可得到密码有()()()三个..2.说明任意两个连续奇数的平方差能被8整](/uploads/image/z/7797235-67-5.jpg?t=1.x%5E4-2%3D%EF%BC%88x-y%EF%BC%89%EF%BC%88x%2By%EF%BC%89%EF%BC%88x%5E2%2By%5E2%EF%BC%89%2C%E5%BD%93x%3D9.y%3D9%E6%97%B6.x-y%3D0.x%2By%3D18.x%5E2%2By%5E2%3D162.%E5%88%99%E8%BF%9E%E8%B5%B7%E6%9D%A5%E4%B8%BA018162%2C%E5%AF%B9%E4%BA%8E%E5%A4%9A%E9%A1%B9%E5%BC%8F%EF%BC%9A4x%5E3-xy%5E2%E5%8F%96x%3D10.y%3D10%E7%94%A8%E4%B8%8A%E8%BF%B0%E6%96%B9%E6%B3%95%E5%8F%AF%E5%BE%97%E5%88%B0%E5%AF%86%E7%A0%81%E6%9C%89%EF%BC%88%EF%BC%89%EF%BC%88%EF%BC%89%28%29%E4%B8%89%E4%B8%AA..2.%E8%AF%B4%E6%98%8E%E4%BB%BB%E6%84%8F%E4%B8%A4%E4%B8%AA%E8%BF%9E%E7%BB%AD%E5%A5%87%E6%95%B0%E7%9A%84%E5%B9%B3%E6%96%B9%E5%B7%AE%E8%83%BD%E8%A2%AB8%E6%95%B4)
1.x^4-2=(x-y)(x+y)(x^2+y^2),当x=9.y=9时.x-y=0.x+y=18.x^2+y^2=162.则连起来为018162,对于多项式:4x^3-xy^2取x=10.y=10用上述方法可得到密码有()()()三个..2.说明任意两个连续奇数的平方差能被8整
1.x^4-2=(x-y)(x+y)(x^2+y^2),当x=9.y=9时.x-y=0.x+y=18.x^2+y^2=162.则连起来为018162,对于多项式:4x^3-xy^2取x=10.y=10用上述方法可得到密码有()()()三个..
2.说明任意两个连续奇数的平方差能被8整除
1.x^4-2=(x-y)(x+y)(x^2+y^2),当x=9.y=9时.x-y=0.x+y=18.x^2+y^2=162.则连起来为018162,对于多项式:4x^3-xy^2取x=10.y=10用上述方法可得到密码有()()()三个..2.说明任意两个连续奇数的平方差能被8整
1)因为4x^3-xy^2=x(4x^2-y^2)=x(2x+y)(2x-y),
当x=10.y=10时,2x+y=30,2x-y=10,
用上述方法可得到密码有:301010,103010,101030三个
2)设任意两个连续奇数为2k+1,2k+3,(k为正整数)
因为(2k+3)^2-(2k+1)^2
=(2k+3+2k+1)(2k+3-2k-1)
=(4k+4)*2
=8(k+1)
所以任意两个连续奇数的平方差能被8整除
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
y'=(y/x)^2+y/x+4微分方程
1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2)/2(x-y)^2
1.(x^3-x^2-4x+1)/(x^2-3x+2)-(x^3-2x^2-9x+21)/(x^2-5x+6)+(x^2-3x+8)/(x^2-4x+3)2.{(x^2)/(x-y)}*{y/(x+y)}-{(x^4y)/(x^4-y^4)}÷{(x^2/x^2+y^2)^2}
X+Y/X=2,X/Y=?是(x+y)/x=2哦
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()
已知(x+y)2 =2,(x-y)3 =3,求(x+y)7(x-y)2(x+y)3(y-x)4 的值
.先化简再求值:(2x+y)(2x+y)-(2x-y)平方其中X,Y满足X平方+Y平方-2X+4Y+5=0
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
(x-y)(x-y)2(y-x) (x+2y-?)(x-2y+?)
(y-x)^4(x-y)^3+2(x-y)^6(y-x)
(x-y)^3×(y-x)^4+(x-y)^2×(y-x)^5
12(x+y)^3(y-x)/【4(x+y)^2(x-y)】
(x-2y)²+(2x-4y)(x+y)+(x+y)²
x(x-2y)=y(2y-x) ,则y分之x是多少
计算:[(x+y)³-2(x+y)²-4(x+y)]÷(x+y)
2分之x+y+3分之x-y;4(x+y)-(x-y)谢谢了,
计算:1.y/4x²-1/12y²+1/6xy 2.3/x-6/1-x-x+5/x²-x3.x/x-y×y²/x+y-x四次方y/x四次方-y四次方÷x²/x²+y²解方程:1.x-1/(x-2)+1=1/2-x2.x+1/x-1-4/x²-1=13.1/x+3-2/3-x=1/x²-9