1/1×2+1/1-1/2:;1/2×4=1/2×(1/2-1/4);1/58×=1/3(×1/5-1/8)(1)根据上面的式子可得,若m、p为正整数,则1/m(m+p)=什么(2)根据上面的规律计算:1/1×3+1/3×5+1/5×7+...+1/99×101
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/26 04:09:47
![1/1×2+1/1-1/2:;1/2×4=1/2×(1/2-1/4);1/58×=1/3(×1/5-1/8)(1)根据上面的式子可得,若m、p为正整数,则1/m(m+p)=什么(2)根据上面的规律计算:1/1×3+1/3×5+1/5×7+...+1/99×101](/uploads/image/z/7967-47-7.jpg?t=1%2F1%C3%972%2B1%2F1-1%2F2%3A%EF%BC%9B1%2F2%C3%974%3D1%2F2%C3%97%EF%BC%881%2F2-1%2F4%EF%BC%89%3B1%2F58%C3%97%3D1%2F3%28%C3%971%2F5-1%2F8%29%281%29%E6%A0%B9%E6%8D%AE%E4%B8%8A%E9%9D%A2%E7%9A%84%E5%BC%8F%E5%AD%90%E5%8F%AF%E5%BE%97%2C%E8%8B%A5m%E3%80%81p%E4%B8%BA%E6%AD%A3%E6%95%B4%E6%95%B0%2C%E5%88%991%2Fm%28m%2Bp%29%3D%E4%BB%80%E4%B9%88%EF%BC%882%EF%BC%89%E6%A0%B9%E6%8D%AE%E4%B8%8A%E9%9D%A2%E7%9A%84%E8%A7%84%E5%BE%8B%E8%AE%A1%E7%AE%97%EF%BC%9A1%2F1%C3%973%2B1%2F3%C3%975%2B1%2F5%C3%977%2B...%2B1%2F99%C3%97101)
1/1×2+1/1-1/2:;1/2×4=1/2×(1/2-1/4);1/58×=1/3(×1/5-1/8)(1)根据上面的式子可得,若m、p为正整数,则1/m(m+p)=什么(2)根据上面的规律计算:1/1×3+1/3×5+1/5×7+...+1/99×101
1/1×2+1/1-1/2:;1/2×4=1/2×(1/2-1/4);1/58×=1/3(×1/5-1/8)
(1)根据上面的式子可得,若m、p为正整数,则1/m(m+p)=什么
(2)根据上面的规律计算:1/1×3+1/3×5+1/5×7+...+1/99×101
1/1×2+1/1-1/2:;1/2×4=1/2×(1/2-1/4);1/58×=1/3(×1/5-1/8)(1)根据上面的式子可得,若m、p为正整数,则1/m(m+p)=什么(2)根据上面的规律计算:1/1×3+1/3×5+1/5×7+...+1/99×101
1)若m、p为正整数,则1/m(m+p)=(1/P)(1/M-1/(M+P)
2)
1/(1*3)=(1/2)(1-1/3)
1/(3*5)=(1/2)(1/3-1/5)
.
1/(99*101)=(1/2)(1/99-1/101)
原式=(1/2)(1-1/3+1/3-1/5+.+1/99-1/101)
=(1/2)(1-1/101)=50/101