计算:x²-6x+9/9-x²除以2x-6/x²+3x
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计算:x²-6x+9/9-x²除以2x-6/x²+3x
计算:x²-6x+9/9-x²除以2x-6/x²+3x
计算:x²-6x+9/9-x²除以2x-6/x²+3x
x²-6x+9/9-x²除以2x-6/x²+3x
=(x²-6x+9)/(9-x²)*(x²+3x)/(2x-6)
=(x-3)^2/[(3-x)(3+x)]*x(3+x)/[2(x-3)]
=x/2