关于函数周期性的f(x+a)=1/f(x)(a不等于0)则f(x)的周期为_____f(x+a)=-1/f(x)则f(x)的周期为_____给结果就行了,
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 01:04:28
![关于函数周期性的f(x+a)=1/f(x)(a不等于0)则f(x)的周期为_____f(x+a)=-1/f(x)则f(x)的周期为_____给结果就行了,](/uploads/image/z/8503180-52-0.jpg?t=%E5%85%B3%E4%BA%8E%E5%87%BD%E6%95%B0%E5%91%A8%E6%9C%9F%E6%80%A7%E7%9A%84f%28x%2Ba%29%3D1%2Ff%28x%29%28a%E4%B8%8D%E7%AD%89%E4%BA%8E0%29%E5%88%99f%28x%29%E7%9A%84%E5%91%A8%E6%9C%9F%E4%B8%BA_____f%28x%2Ba%29%3D-1%2Ff%28x%29%E5%88%99f%28x%29%E7%9A%84%E5%91%A8%E6%9C%9F%E4%B8%BA_____%E7%BB%99%E7%BB%93%E6%9E%9C%E5%B0%B1%E8%A1%8C%E4%BA%86%2C)
关于函数周期性的f(x+a)=1/f(x)(a不等于0)则f(x)的周期为_____f(x+a)=-1/f(x)则f(x)的周期为_____给结果就行了,
关于函数周期性的
f(x+a)=1/f(x)(a不等于0)则f(x)的周期为_____
f(x+a)=-1/f(x)则f(x)的周期为_____
给结果就行了,
关于函数周期性的f(x+a)=1/f(x)(a不等于0)则f(x)的周期为_____f(x+a)=-1/f(x)则f(x)的周期为_____给结果就行了,
f(x+a)=1/f(x)(a不等于0)则f(x)的周期为___2a__
f(x+a)=-1/f(x)则f(x)的周期为_2a__
1. f(x+2a)=f(x+a+a)=1/f(x+a)=f(x) 所以周期是2a
2 f(x+2a)=f(x+a+a)=-1/f(x+a)=-(-f(x))=f(x) 周期也是2a
两个都是2a
你要的结果是
(1)2a
(2)2a