设集合A={y| y= x^2-4x+3,x∈R},集合B={m|m=-n^2-2n,n∈R},求A∩B,A∪B
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![设集合A={y| y= x^2-4x+3,x∈R},集合B={m|m=-n^2-2n,n∈R},求A∩B,A∪B](/uploads/image/z/8732733-69-3.jpg?t=%E8%AE%BE%E9%9B%86%E5%90%88A%3D%EF%BD%9By%7C+y%3D+x%5E2-4x%2B3%2Cx%E2%88%88R%EF%BD%9D%2C%E9%9B%86%E5%90%88B%3D%7Bm%7Cm%3D-n%5E2-2n%2Cn%E2%88%88R%EF%BD%9D%2C%E6%B1%82A%E2%88%A9B%2CA%E2%88%AAB)
设集合A={y| y= x^2-4x+3,x∈R},集合B={m|m=-n^2-2n,n∈R},求A∩B,A∪B
设集合A={y| y= x^2-4x+3,x∈R},集合B={m|m=-n^2-2n,n∈R},求A∩B,A∪B
设集合A={y| y= x^2-4x+3,x∈R},集合B={m|m=-n^2-2n,n∈R},求A∩B,A∪B
y=x^2-4x+3=(x-2)^2-1>=-1
所以A是大于等于-1的实数的集合
m=-n^2-2n=-(n+1)+1