设全集U=(x/x≥0),集合A=(x/1<x≤2),则cuA =?A∩cuA =?A∪cuA ?
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![设全集U=(x/x≥0),集合A=(x/1<x≤2),则cuA =?A∩cuA =?A∪cuA ?](/uploads/image/z/8825090-50-0.jpg?t=%E8%AE%BE%E5%85%A8%E9%9B%86U%3D%EF%BC%88x%2Fx%E2%89%A50%EF%BC%89%2C%E9%9B%86%E5%90%88A%3D%EF%BC%88x%2F1%EF%BC%9Cx%E2%89%A42%EF%BC%89%2C%E5%88%99cuA+%3D%3FA%E2%88%A9cuA+%3D%3FA%E2%88%AAcuA+%3F)
设全集U=(x/x≥0),集合A=(x/1<x≤2),则cuA =?A∩cuA =?A∪cuA ?
设全集U=(x/x≥0),集合A=(x/1<x≤2),则cuA =?A∩cuA =?A∪cuA ?
设全集U=(x/x≥0),集合A=(x/1<x≤2),则cuA =?A∩cuA =?A∪cuA ?
CuA={x|0≤x≤1或者x>2}
A∩cuA =Φ
A∪cuA =U