(1/x²+x)+(1/x²+3x+2)+(1/x²+5x+6)+(x²+7x+12)+(x²+9x+20)=5/x²+11x-708 怎么解方程啊
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![(1/x²+x)+(1/x²+3x+2)+(1/x²+5x+6)+(x²+7x+12)+(x²+9x+20)=5/x²+11x-708 怎么解方程啊](/uploads/image/z/958931-35-1.jpg?t=%EF%BC%881%2Fx%26%23178%3B%2Bx%EF%BC%89%2B%EF%BC%881%2Fx%26%23178%3B%2B3x%2B2%EF%BC%89%2B%EF%BC%881%2Fx%26%23178%3B%2B5x%2B6%EF%BC%89%2B%EF%BC%88x%26%23178%3B%2B7x%2B12%EF%BC%89%2B%EF%BC%88x%26%23178%3B%2B9x%2B20%EF%BC%89%3D5%2Fx%26%23178%3B%2B11x-708+++++++++%E6%80%8E%E4%B9%88%E8%A7%A3%E6%96%B9%E7%A8%8B%E5%95%8A)
(1/x²+x)+(1/x²+3x+2)+(1/x²+5x+6)+(x²+7x+12)+(x²+9x+20)=5/x²+11x-708 怎么解方程啊
(1/x²+x)+(1/x²+3x+2)+(1/x²+5x+6)+(x²+7x+12)+(x²+9x+20)=5/x²+11x-708 怎么解方程啊
(1/x²+x)+(1/x²+3x+2)+(1/x²+5x+6)+(x²+7x+12)+(x²+9x+20)=5/x²+11x-708 怎么解方程啊
现将括号打开 再利用换元的思想 最后合并同类项