已知A,B互为相反数,X,Y互为倒数,C的绝对值=3,求1/3C^3(XY)^3-2/3C^2(A+B)^2-4/3C^3(XY)^3
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![已知A,B互为相反数,X,Y互为倒数,C的绝对值=3,求1/3C^3(XY)^3-2/3C^2(A+B)^2-4/3C^3(XY)^3](/uploads/image/z/997960-40-0.jpg?t=%E5%B7%B2%E7%9F%A5A%2CB%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2CX%2CY%E4%BA%92%E4%B8%BA%E5%80%92%E6%95%B0%2CC%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%3D3%2C%E6%B1%821%2F3C%5E3%28XY%29%5E3-2%2F3C%5E2%28A%2BB%29%5E2-4%2F3C%5E3%28XY%29%5E3)
已知A,B互为相反数,X,Y互为倒数,C的绝对值=3,求1/3C^3(XY)^3-2/3C^2(A+B)^2-4/3C^3(XY)^3
已知A,B互为相反数,X,Y互为倒数,C的绝对值=3,求1/3C^3(XY)^3-2/3C^2(A+B)^2-4/3C^3(XY)^3
已知A,B互为相反数,X,Y互为倒数,C的绝对值=3,求1/3C^3(XY)^3-2/3C^2(A+B)^2-4/3C^3(XY)^3
1/3C^3(XY)^3-2/3C^2(A+B)^2-4/3C^3(XY)^3
=1/3C^3-0-4/3C^3
=-C^3
=27或-27
因为c的绝对值=3所以c=正负3因为A,B互为相反数所以a+b=0因为X,Y互为倒数所以xy=1
根据题意得:
A+B=0
XY=1
C=3或-3
(1/3)*C^3*(XY)^3-(2/3)*C^2*(A+B)^2-(4/3)*C^3*(XY)^3
=(1/3)*27*1-0-(4/3)*27*1
=9-0-36
=9-36
=-27
(1/3)*C^3*(XY)^3-(2/3)*C^2*(A+B)^2-(4/3)*C^3*(XY)^3
=(1/3)*(-27)*1-0-(4/3)*(-27)*1
=-9-0+36
=-9+36
=27
根据题意得:
A+B=0
XY=1
C=3或-3
(1/3)*C^3*(XY)^3-(2/3)*C^2*(A+B)^2-(4/3)*C^3*(XY)^3
=(1/3)*27*1-0-(4/3)*27*1
=9-0-36
=9-36
=-27
(1/3)*C^3*(XY)^3-(2/3)*C^2*(A+B)^2-(4/3)*C^3*(XY)^3
=(1/3)*(-27)*1-0-(4/3)*(-27)*1
=-9-0+36
=-9+36
=27 就是这样