计算下列两道题
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/26 06:13:41
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计算下列两道题
计算下列两道题
计算下列两道题
(1)原式=√12 - √3 x (2 - √3)/(4-3)=2√3 - 2√3 + 3=3
(2)原式=(3+2-2√6)+ 4(√6 - 2)/(6-2)=5-2√6 +√6 -2=3-√6
(1)√12-√3/(2+√3)
=√12-√3(2-√3)/(2+√3)(2-√3)
=√12-2√3+3
=2√3-2√3+3
=3
(2) (√3-√2)² +4/(√6+2)
=3-2√6+2+4(√6-...
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(1)√12-√3/(2+√3)
=√12-√3(2-√3)/(2+√3)(2-√3)
=√12-2√3+3
=2√3-2√3+3
=3
(2) (√3-√2)² +4/(√6+2)
=3-2√6+2+4(√6-2)/(√6+2)(√6-2)
=5-2√6+4(√6-2)/2
=5-2√6+2(√6-2)
=5-2√6+2√6-4
=1
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