先化简分式(1加a分之b)乘以[(a减b)分之1减(a加b)分之一],并求出当a,b满足式子a^2加b^2减6a减2b加10=0时分式的值
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![先化简分式(1加a分之b)乘以[(a减b)分之1减(a加b)分之一],并求出当a,b满足式子a^2加b^2减6a减2b加10=0时分式的值](/uploads/image/z/10287873-9-3.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%88%86%E5%BC%8F%EF%BC%881%E5%8A%A0a%E5%88%86%E4%B9%8Bb%EF%BC%89%E4%B9%98%E4%BB%A5%5B%EF%BC%88a%E5%87%8Fb%EF%BC%89%E5%88%86%E4%B9%8B1%E5%87%8F%EF%BC%88a%E5%8A%A0b%EF%BC%89%E5%88%86%E4%B9%8B%E4%B8%80%5D%2C%E5%B9%B6%E6%B1%82%E5%87%BA%E5%BD%93a%2Cb%E6%BB%A1%E8%B6%B3%E5%BC%8F%E5%AD%90a%5E2%E5%8A%A0b%5E2%E5%87%8F6a%E5%87%8F2b%E5%8A%A010%EF%BC%9D0%E6%97%B6%E5%88%86%E5%BC%8F%E7%9A%84%E5%80%BC)
先化简分式(1加a分之b)乘以[(a减b)分之1减(a加b)分之一],并求出当a,b满足式子a^2加b^2减6a减2b加10=0时分式的值
先化简分式(1加a分之b)乘以[(a减b)分之1减(a加b)分之一],并求出当a,b满足式子a^2加b^2减6a减2b加10=0时分式的值
先化简分式(1加a分之b)乘以[(a减b)分之1减(a加b)分之一],并求出当a,b满足式子a^2加b^2减6a减2b加10=0时分式的值
b/(1+a)*[1/(a-b)-1/(a+b)]=b/(1+a)*(a^2-b^2)/2b=(a^2-b^2)/(2+2a)
a^2+b^2-6a-2b+10=0
∴(a-3)^2+(b-1)^2=0
∴a=3,b=1
∴原式=(3^2-1^2)/(2+2*3)=1
(1加a分之b)乘以[(a减b)分之1减(a加b)分之一]÷
=(1+b/a)×[1/(a-b)-1/(a+b)]
=(a/a+b/a)×[(a+b)/(a-b)(a+b)-(a-b)/(a+b)(a-b)]
=(a+b)/a×[(a+b)-(a-b)/(a+b)(a-b)]
=(a+b)/a×2b/(a+b)(a-b)
=2b/a(a-b)
a...
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(1加a分之b)乘以[(a减b)分之1减(a加b)分之一]÷
=(1+b/a)×[1/(a-b)-1/(a+b)]
=(a/a+b/a)×[(a+b)/(a-b)(a+b)-(a-b)/(a+b)(a-b)]
=(a+b)/a×[(a+b)-(a-b)/(a+b)(a-b)]
=(a+b)/a×2b/(a+b)(a-b)
=2b/a(a-b)
a²+b²-6a-2b+10=0
a²-6a+9+b²-2b+1=0
(a-3)²+(b-1)²=0
a=3
b=1
原式=2×1/3(3-1)
=2/6
=1/3
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1加a分之b)乘以[(a减b)分之1减(a加b)分之一]
=(1+b/a))×(1/(a-b)-1/(a+b))
=((a+b)/a))×(a+b-a+b)/(a²-b²)
=((a+b)/a)×(2b)/(a²-b²)
=2b/a(a-b);
a^2加b^2减6a减2b加10=0;
(a-3)²+(b-1)²=0;
a-3=b-1=0;
a=3;b=1;
∴原式=2/3(3-1)=1/3;
先化简分式(1加a分之b)乘以[(a减b)分之1减(a加b)分之一],
=(a+b)/a *[(a+b-a+b)/(a-b)(a+b)]
=(a+b)/a * 2b/(a-b)(a+b)
=2b/a(a-b)
当a,b满足式子a^2加b^2减6a减2b加10=0
a^2+b^2-6a-2b+10=0
a^2-6a+9+b^2-2b+1=0
(...
全部展开
先化简分式(1加a分之b)乘以[(a减b)分之1减(a加b)分之一],
=(a+b)/a *[(a+b-a+b)/(a-b)(a+b)]
=(a+b)/a * 2b/(a-b)(a+b)
=2b/a(a-b)
当a,b满足式子a^2加b^2减6a减2b加10=0
a^2+b^2-6a-2b+10=0
a^2-6a+9+b^2-2b+1=0
(a-3)^2+(b-1)^2=0
则有a=3 b=1
分式=2b/a(a-b)
=2*1/3*(3-1)
=1/3
收起