初二分母有理化1、√3/√6-√52、(1/√5-2)²3、5/(4-√11)+1/ (3+√7)-6/(√7-2)-(√7-5)/2
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 17:26:35
![初二分母有理化1、√3/√6-√52、(1/√5-2)²3、5/(4-√11)+1/ (3+√7)-6/(√7-2)-(√7-5)/2](/uploads/image/z/10330614-54-4.jpg?t=%E5%88%9D%E4%BA%8C%E5%88%86%E6%AF%8D%E6%9C%89%E7%90%86%E5%8C%961%E3%80%81%E2%88%9A3%2F%E2%88%9A6-%E2%88%9A52%E3%80%81%EF%BC%881%2F%E2%88%9A5-2%EF%BC%89%26%23178%3B3%E3%80%815%2F%284-%E2%88%9A11%29%2B1%2F+%283%2B%E2%88%9A7%29-6%2F%EF%BC%88%E2%88%9A7-2%EF%BC%89-%EF%BC%88%E2%88%9A7-5%EF%BC%89%2F2)
初二分母有理化1、√3/√6-√52、(1/√5-2)²3、5/(4-√11)+1/ (3+√7)-6/(√7-2)-(√7-5)/2
初二分母有理化
1、√3/√6-√5
2、(1/√5-2)²
3、5/(4-√11)+1/ (3+√7)-6/(√7-2)-(√7-5)/2
初二分母有理化1、√3/√6-√52、(1/√5-2)²3、5/(4-√11)+1/ (3+√7)-6/(√7-2)-(√7-5)/2
1、√3/√6-√5=√3(√6+√5)=3√2+√15
2、(1/√5-2)²=[√5+2/(√5-2)(√5+2)]²=(√5+2)²=9+4√5
3、5/(4-√11)+1/ (3+√7)-6/(√7-2)-(√7-5)/2
=5(4+√11)/5+(3-√7)/2-6(√7+2)/3-(√7-5)/2
=4+√11+3/2-1/2√7-2√7-4-1/2√7+5/2
=8+√11-3√7
1、原式=√3(√6+√5)/(6-5)
=√3(√6+√5)/1
=3√2+√15
2、原式=[(√5+2)/(5-4)]²
=(√5+2)²
=9+4√5
3、原式=5(4+√11)/(16-11)+(3-√7)/(9-7)-6(√7+2)/(7-4)-(√7-5)/2
=4+√11+(3-√7...
全部展开
1、原式=√3(√6+√5)/(6-5)
=√3(√6+√5)/1
=3√2+√15
2、原式=[(√5+2)/(5-4)]²
=(√5+2)²
=9+4√5
3、原式=5(4+√11)/(16-11)+(3-√7)/(9-7)-6(√7+2)/(7-4)-(√7-5)/2
=4+√11+(3-√7)/2-2(√7+2)-(√7-5)/2
=(4+√11-2√7-4)+(3-√7-√7+5)/2
=√11-2√7+4-√7
=4+√11-3√7
望采纳,谢谢!
收起