这题之后的步骤是怎么推导出来的?x=4,代入x2/4-y2/3=1所以P(4,3)A1(-2,0),A2(2,0)则PA1是x-2y+2=0PA2是3x-2y-6=0PA1:x=2y-2代入x2/4+y2/3=12y2-3y=0y=3/2,x=1所以Q(1,3/2)PA1:y=3x/2-3代入x2/4+y2/3=12y2-3y=0y=3/2,x=1所以Q(1,3/2)x=1,y
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![这题之后的步骤是怎么推导出来的?x=4,代入x2/4-y2/3=1所以P(4,3)A1(-2,0),A2(2,0)则PA1是x-2y+2=0PA2是3x-2y-6=0PA1:x=2y-2代入x2/4+y2/3=12y2-3y=0y=3/2,x=1所以Q(1,3/2)PA1:y=3x/2-3代入x2/4+y2/3=12y2-3y=0y=3/2,x=1所以Q(1,3/2)x=1,y](/uploads/image/z/10392462-54-2.jpg?t=%E8%BF%99%E9%A2%98%E4%B9%8B%E5%90%8E%E7%9A%84%E6%AD%A5%E9%AA%A4%E6%98%AF%E6%80%8E%E4%B9%88%E6%8E%A8%E5%AF%BC%E5%87%BA%E6%9D%A5%E7%9A%84%3Fx%3D4%2C%E4%BB%A3%E5%85%A5x2%2F4-y2%2F3%3D1%E6%89%80%E4%BB%A5P%284%2C3%29A1%28-2%2C0%29%2CA2%282%2C0%29%E5%88%99PA1%E6%98%AFx-2y%2B2%3D0PA2%E6%98%AF3x-2y-6%3D0PA1%3Ax%3D2y-2%E4%BB%A3%E5%85%A5x2%2F4%2By2%2F3%3D12y2-3y%3D0y%3D3%2F2%2Cx%3D1%E6%89%80%E4%BB%A5Q%281%2C3%2F2%29PA1%3Ay%3D3x%2F2-3%E4%BB%A3%E5%85%A5x2%2F4%2By2%2F3%3D12y2-3y%3D0y%3D3%2F2%2Cx%3D1%E6%89%80%E4%BB%A5Q%281%2C3%2F2%29x%3D1%2Cy)
这题之后的步骤是怎么推导出来的?x=4,代入x2/4-y2/3=1所以P(4,3)A1(-2,0),A2(2,0)则PA1是x-2y+2=0PA2是3x-2y-6=0PA1:x=2y-2代入x2/4+y2/3=12y2-3y=0y=3/2,x=1所以Q(1,3/2)PA1:y=3x/2-3代入x2/4+y2/3=12y2-3y=0y=3/2,x=1所以Q(1,3/2)x=1,y
这题之后的步骤是怎么推导出来的?
x=4,代入x2/4-y2/3=1
所以P(4,3)
A1(-2,0),A2(2,0)
则PA1是x-2y+2=0
PA2是3x-2y-6=0
PA1:x=2y-2
代入x2/4+y2/3=1
2y2-3y=0
y=3/2,x=1
所以Q(1,3/2)
PA1:y=3x/2-3
代入x2/4+y2/3=1
2y2-3y=0
y=3/2,x=1
所以Q(1,3/2)
x=1,y=-3/2
R(1,-3/2)
所以QR=3/2-(-3/2)=3
这题之后的步骤是怎么推导出来的?x=4,代入x2/4-y2/3=1所以P(4,3)A1(-2,0),A2(2,0)则PA1是x-2y+2=0PA2是3x-2y-6=0PA1:x=2y-2代入x2/4+y2/3=12y2-3y=0y=3/2,x=1所以Q(1,3/2)PA1:y=3x/2-3代入x2/4+y2/3=12y2-3y=0y=3/2,x=1所以Q(1,3/2)x=1,y
P(4,3),A1(-2,0)
假设x1=4,x2=-2
y1=3,y2=0
则(x-4)/(-2-4)=(y-3)/(0-3)
x-4=2y-6
x-2y+2=0
若是x1=-2,x2=4
y1=0,y2=3
则(x+2)/(4+2)=(y-0)/(3-0)
x+2=2y
也是x-2y+2=0
PA2同理可得