高中生物有关DNAJ计算题 若(A+T)/(A+T+G+C)=54%,G1/(A1+T1+G1+C1)=22%求G2/(A2+T2+G2+C2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/17 01:09:42
![高中生物有关DNAJ计算题 若(A+T)/(A+T+G+C)=54%,G1/(A1+T1+G1+C1)=22%求G2/(A2+T2+G2+C2)](/uploads/image/z/11297207-47-7.jpg?t=%E9%AB%98%E4%B8%AD%E7%94%9F%E7%89%A9%E6%9C%89%E5%85%B3DNAJ%E8%AE%A1%E7%AE%97%E9%A2%98+%E8%8B%A5%28A%2BT%29%2F%28A%2BT%2BG%2BC%29%3D54%25%2CG1%2F%28A1%2BT1%2BG1%2BC1%29%3D22%25%E6%B1%82G2%2F%28A2%2BT2%2BG2%2BC2%29)
高中生物有关DNAJ计算题 若(A+T)/(A+T+G+C)=54%,G1/(A1+T1+G1+C1)=22%求G2/(A2+T2+G2+C2)
高中生物有关DNAJ计算题 若(A+T)/(A+T+G+C)=54%,G1/(A1+T1+G1+C1)=22%
求G2/(A2+T2+G2+C2)
高中生物有关DNAJ计算题 若(A+T)/(A+T+G+C)=54%,G1/(A1+T1+G1+C1)=22%求G2/(A2+T2+G2+C2)
若(A+T)/(A+T+G+C)=54%,得(G+C)/(A+T+G+C)=46%,在DNA双链中,由于A=T,G=C,所以双链上A+T与G+C的比值与每条单链上此碱基之和占该单链的比值是相等的,即(A1+T1)/(A1+T1+G1+C1)=(A2+T2)/(A2+T2+G2+C2)=54%,(G1+C1)/(A1+T1+G1+C1)=(G2+C2)/(A2+T2+G2+C2)=46%,由G1/(A1+T1+G1+C1)=22% 得C1/(A1+T1+G1+C1)=46%-22%=24%,根据碱基互补配对原则,G2/(A2+T2+G2+C2)=C1/(A1+T1+G1+C1)=24%.
因为(A+T)/(A+T+G+C)=54% 所以双链上的A+T为全部的54% 所以C+G为全部的46% G为全部的23% 又因为G1/(A1+T1+G1+C1)=22% 所以G1/(A+T+G+C)=11% 所以G2=23%-11%=12%
(C1+G1)/(A1+T1+G1+C1)=(C+G)/(A+T+C+G)=46/100
G2/(A2+T2+G2+C2)=C1/(A1+T1+G1+C1)
=(C1+G1)/(A1+T1+G1+C1)-G1/(A1+T1+G1+C1)
=46/100-22/100=24/100