mathematica 小数位保留问题用一个方程组计算X,Y,Z,最后输出结果我需要保留X,Y,Z小数点后10位,请问如何能做到? NSolve[{ (35902.563 - x)^2 + (27961.019 - y)^2 + (-5000 - z)^2 == 7685.756^2, (37171.632 - x)^2 + (34797.071
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![mathematica 小数位保留问题用一个方程组计算X,Y,Z,最后输出结果我需要保留X,Y,Z小数点后10位,请问如何能做到? NSolve[{ (35902.563 - x)^2 + (27961.019 - y)^2 + (-5000 - z)^2 == 7685.756^2, (37171.632 - x)^2 + (34797.071](/uploads/image/z/11372861-29-1.jpg?t=mathematica+%E5%B0%8F%E6%95%B0%E4%BD%8D%E4%BF%9D%E7%95%99%E9%97%AE%E9%A2%98%E7%94%A8%E4%B8%80%E4%B8%AA%E6%96%B9%E7%A8%8B%E7%BB%84%E8%AE%A1%E7%AE%97X%2CY%2CZ%2C%E6%9C%80%E5%90%8E%E8%BE%93%E5%87%BA%E7%BB%93%E6%9E%9C%E6%88%91%E9%9C%80%E8%A6%81%E4%BF%9D%E7%95%99X%2CY%2CZ%E5%B0%8F%E6%95%B0%E7%82%B9%E5%90%8E10%E4%BD%8D%2C%E8%AF%B7%E9%97%AE%E5%A6%82%E4%BD%95%E8%83%BD%E5%81%9A%E5%88%B0%3F+NSolve%5B%7B+%2835902.563+-+x%29%5E2+%2B+%2827961.019+-+y%29%5E2+%2B+%28-5000+-+z%29%5E2+%3D%3D+7685.756%5E2%2C+%2837171.632+-+x%29%5E2+%2B+%2834797.071)
mathematica 小数位保留问题用一个方程组计算X,Y,Z,最后输出结果我需要保留X,Y,Z小数点后10位,请问如何能做到? NSolve[{ (35902.563 - x)^2 + (27961.019 - y)^2 + (-5000 - z)^2 == 7685.756^2, (37171.632 - x)^2 + (34797.071
mathematica 小数位保留问题
用一个方程组计算X,Y,Z,最后输出结果我需要保留X,Y,Z小数点后10位,请问如何能做到? NSolve[{ (35902.563 - x)^2 + (27961.019 - y)^2 + (-5000 - z)^2 == 7685.756^2, (37171.632 - x)^2 + (34797.071 - y)^2 + (-5623 - z)^2 == 8313.475^2, (43459.139 - x)^2 + (29358.478 - y)^2 + (-5300 - z)^2 == 5786.234^2}, {x, y, z}] 输出的结果: {{x -> 41035.3, y -> 29331.6, z -> -10554.}, {x -> 41284.7, y -> 30246.1, z -> -11.8493}} 我知道我输入的数值中含有小数,输出的值只会有6位有效数.但不知道怎么改更高精度?望高手赐教.谢谢!
mathematica 小数位保留问题用一个方程组计算X,Y,Z,最后输出结果我需要保留X,Y,Z小数点后10位,请问如何能做到? NSolve[{ (35902.563 - x)^2 + (27961.019 - y)^2 + (-5000 - z)^2 == 7685.756^2, (37171.632 - x)^2 + (34797.071
比如说你要五十位,也就输入: NSolve[{ (35902563/1000 - x)^2 + (27961019/1000 - y)^2 + (-5000 - z)^2 == (7685756/1000)^2, (37171632/1000 - x)^2 + (34797071/1000 - y)^2 + (-5623 - z)^2 == (8313475/1000)^2, (43459139/1000 - x)^2 + (29358478/1000 - y)^2 + (-5300 - z)^2 == (5786234/1000)^2}, {x, y, z},50] 即可 要注意原方程中的小数最好改为分数.