导数A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are initially 2000 bacteria,then how many bacteria will there be after one week.1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),20
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![导数A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are initially 2000 bacteria,then how many bacteria will there be after one week.1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),20](/uploads/image/z/12538263-39-3.jpg?t=%E5%AF%BC%E6%95%B0A+bacteria+population+is+growing+at+1000e%5E-0.2x+bacteria+per+day.If+there+are+initially+2000+bacteria%2Cthen+how+many+bacteria+will+there+be+after+one+week.1%E4%B8%AA%E7%BB%86%E8%83%9E%E6%AF%8F%E5%A4%A9%E5%A2%9E%E5%8A%A01000e%5E-0.2x%2C%E4%B8%80%E5%91%A87%E5%A4%A9%2C%E9%82%A31%E4%B8%AA%E7%BB%86%E8%83%9E%E6%AF%8F%E5%A4%A9%E5%B0%B1%E6%98%AF1000e%5E-0.2%EF%BC%887%EF%BC%89%2C20)
导数A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are initially 2000 bacteria,then how many bacteria will there be after one week.1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),20
导数
A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are
initially 2000 bacteria,then how many bacteria will there be after one week.
1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),2000个就是2000*1000e^-0.2(7)
请问为什么不能这么算?正确算法是用反导
导数A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are initially 2000 bacteria,then how many bacteria will there be after one week.1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),20
1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞7天就是增加1000e^-0.2(7)才对,可是问的是2000个细胞一周后数量为多少并非问2000个细胞一周后增加的的数目,你可以类比啊,条件给出的相当于速度,实际求位移,你说是不是用反导啊
是曲线还是切线?
满意请采纳。