设数列a1=a,an+1=an^2+a1,当a属于(0,1/4]时,求证:an的绝对值小于等于2
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![设数列a1=a,an+1=an^2+a1,当a属于(0,1/4]时,求证:an的绝对值小于等于2](/uploads/image/z/12635527-31-7.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97a1%3Da%2Can%2B1%3Dan%5E2%2Ba1%2C%E5%BD%93a%E5%B1%9E%E4%BA%8E%280%2C1%2F4%5D%E6%97%B6%2C%E6%B1%82%E8%AF%81%3Aan%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E2)
设数列a1=a,an+1=an^2+a1,当a属于(0,1/4]时,求证:an的绝对值小于等于2
设数列a1=a,an+1=an^2+a1,当a属于(0,1/4]时,求证:an的绝对值小于等于2
设数列a1=a,an+1=an^2+a1,当a属于(0,1/4]时,求证:an的绝对值小于等于2
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