已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2+4x+4)]/[(x^2-x+1)/(x-2)]

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已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2+4x+4)]/[(x^2-x+1)/(x-2)]

已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2+4x+4)]/[(x^2-x+1)/(x-2)]
已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2
已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2+4x+4)]/[(x^2-x+1)/(x-2)]

已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2+4x+4)]/[(x^2-x+1)/(x-2)]
把x2+7x+10化成(x+2)(x+5)同理就可以约分了最后约分成最简,把想=9/2代入,就可以啦