(1g2)^3+(1g5)^3+31g2*1g5=?

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(1g2)^3+(1g5)^3+31g2*1g5=?

(1g2)^3+(1g5)^3+31g2*1g5=?
(1g2)^3+(1g5)^3+31g2*1g5=?

(1g2)^3+(1g5)^3+31g2*1g5=?
(1g2)^3+(1g5)^3+31g2*1g5
＝(lg2+lg5)[(lg2)^2+(lg5)^2-lg2lg5]+31g2*1g5
=[(lg2)^2+(lg5)^2-lg2lg5]+31g2*1g5
=[(lg2)^2+(lg5)^2+2lg2lg5]
=(lg2+lg5)^2
=1

(1g2)^3+(1g5)^3+31g2*1g5
=(lg2+lg5)[(1g2)^2+(1g5)^2-1g2*1g5]+31g2*1g5
=[(1g2)^2+(1g5)^2-1g2*1g5]+31g2*1g5
=(1g2)^2+(1g5)^2+21g2*1g5
=(lg2+lg5)^2
=1^2
=1

(1g2)^3+(1g5)^3+31g2*1g5=? 化简求值 (1g2)^3+(1g5)^3+3*1g2*1g5 (1g5)+21g2-(1g2) 1g2+1g5= 1g2+1g5等于 已知a+b=(1g2)^3+(1g2)^5+31g2*1g5,求3ab+a^3+b^3的值 已知a+b=(1g2)^3+(1g2)^5+31g2*1g5,求3ab+a^3+b^3的值 解(1g2)^3+(1g5)^3+1g5*1g8 1g5^2+1g8^(2/3)+1g5·1g20+(1g2)^2= lg5+lg2*1g5+(1g2)^2 1g5-1g2份之一 计算 1g5+1g2等于多少. 1g2+1g5+(-8)的-1/3次方 过程 在此可以跟我解释一下,1g2+1g5怎么算 1g25+2/3g8+1g5乘1g20+(1g2)的平方 (1g5)的2平方+21g2-(1g2)的2平方 ( 1g5 )^2+21g2-( 1g2)^2计算此题. (1g2)的二次方+1g20乘以1g5 计算(1g5)2+1g2*1g50=多少?