r语言中,with,which用法的问题,b b b[1] 101 102> with(subset(recommendation[user==1,]),which(item==101))[1] 1> with(subset(recommendation[user==1,]),which(item==102))[1] 3> with(subset(recommendation[user==1,]),which(b%in%item))[1] 1 2应该输
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![r语言中,with,which用法的问题,b b b[1] 101 102> with(subset(recommendation[user==1,]),which(item==101))[1] 1> with(subset(recommendation[user==1,]),which(item==102))[1] 3> with(subset(recommendation[user==1,]),which(b%in%item))[1] 1 2应该输](/uploads/image/z/13437157-13-7.jpg?t=r%E8%AF%AD%E8%A8%80%E4%B8%AD%2Cwith%2Cwhich%E7%94%A8%E6%B3%95%E7%9A%84%E9%97%AE%E9%A2%98%2Cb+b+b%5B1%5D+101+102%3E+with%28subset%28recommendation%5Buser%3D%3D1%2C%5D%29%2Cwhich%28item%3D%3D101%29%29%5B1%5D+1%3E+with%28subset%28recommendation%5Buser%3D%3D1%2C%5D%29%2Cwhich%28item%3D%3D102%29%29%5B1%5D+3%3E+with%28subset%28recommendation%5Buser%3D%3D1%2C%5D%29%2Cwhich%28b%25in%25item%29%29%5B1%5D+1+2%E5%BA%94%E8%AF%A5%E8%BE%93)
r语言中,with,which用法的问题,b b b[1] 101 102> with(subset(recommendation[user==1,]),which(item==101))[1] 1> with(subset(recommendation[user==1,]),which(item==102))[1] 3> with(subset(recommendation[user==1,]),which(b%in%item))[1] 1 2应该输
r语言中,with,which用法的问题,
b b b
[1] 101 102
> with(subset(recommendation[user==1,]),which(item==101))
[1] 1
> with(subset(recommendation[user==1,]),which(item==102))
[1] 3
> with(subset(recommendation[user==1,]),which(b%in%item))
[1] 1 2
应该输出1和3呀怎么是2
r语言中,with,which用法的问题,b b b[1] 101 102> with(subset(recommendation[user==1,]),which(item==101))[1] 1> with(subset(recommendation[user==1,]),which(item==102))[1] 3> with(subset(recommendation[user==1,]),which(b%in%item))[1] 1 2应该输
这个是which(item.x==101)),不是which(item==101))吧
还有which(b%in%item.x))
一开始有item.x这一列元素的,后面怎么都是item了呀?
你能把信息再补充多一点吗?譬如把 m 给出来看一下.