帮忙接一个二元一次方程,解出有分加.-2=[(根号3)/3]*x^2 -(2根号3)/3*x*-根号3
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![帮忙接一个二元一次方程,解出有分加.-2=[(根号3)/3]*x^2 -(2根号3)/3*x*-根号3](/uploads/image/z/15030815-23-5.jpg?t=%E5%B8%AE%E5%BF%99%E6%8E%A5%E4%B8%80%E4%B8%AA%E4%BA%8C%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%2C%E8%A7%A3%E5%87%BA%E6%9C%89%E5%88%86%E5%8A%A0.-2%3D%5B%28%E6%A0%B9%E5%8F%B73%29%2F3%5D%2Ax%5E2+-%EF%BC%882%E6%A0%B9%E5%8F%B73%EF%BC%89%2F3%2Ax%2A-%E6%A0%B9%E5%8F%B73)
帮忙接一个二元一次方程,解出有分加.-2=[(根号3)/3]*x^2 -(2根号3)/3*x*-根号3
帮忙接一个二元一次方程,解出有分加.
-2=[(根号3)/3]*x^2 -(2根号3)/3*x*-根号3
帮忙接一个二元一次方程,解出有分加.-2=[(根号3)/3]*x^2 -(2根号3)/3*x*-根号3
-2=[(根号3)/3]*x^2 -(2根号3)/3*x*-根号3
x^2-2x+2√3-3=0
x={2±√[4-4(2√3-3)]}/2
=1±√(1-2√3+3)
=1±√(4-2√3)
=1±(√3-1)
=√3或2-√3
实数范围内无解
△=b^2-4ac=-8√3/3-8/3<0
x=根号3
x=2-根号3