(3+2√2)的十次方乘以(1-√2)的十九次方+(√2+1)的负一次方减(2√2减3)的零次方求完整详细过程或思路,
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![(3+2√2)的十次方乘以(1-√2)的十九次方+(√2+1)的负一次方减(2√2减3)的零次方求完整详细过程或思路,](/uploads/image/z/217601-17-1.jpg?t=%EF%BC%883%2B2%E2%88%9A2%EF%BC%89%E7%9A%84%E5%8D%81%E6%AC%A1%E6%96%B9%E4%B9%98%E4%BB%A5%EF%BC%881-%E2%88%9A2%EF%BC%89%E7%9A%84%E5%8D%81%E4%B9%9D%E6%AC%A1%E6%96%B9%2B%EF%BC%88%E2%88%9A2%2B1%EF%BC%89%E7%9A%84%E8%B4%9F%E4%B8%80%E6%AC%A1%E6%96%B9%E5%87%8F%EF%BC%882%E2%88%9A2%E5%87%8F3%EF%BC%89%E7%9A%84%E9%9B%B6%E6%AC%A1%E6%96%B9%E6%B1%82%E5%AE%8C%E6%95%B4%E8%AF%A6%E7%BB%86%E8%BF%87%E7%A8%8B%E6%88%96%E6%80%9D%E8%B7%AF%2C)
(3+2√2)的十次方乘以(1-√2)的十九次方+(√2+1)的负一次方减(2√2减3)的零次方求完整详细过程或思路,
(3+2√2)的十次方乘以(1-√2)的十九次方+(√2+1)的负一次方减(2√2减3)的零次方
求完整详细过程或思路,
(3+2√2)的十次方乘以(1-√2)的十九次方+(√2+1)的负一次方减(2√2减3)的零次方求完整详细过程或思路,
(3+2√2)^10*(1-√2)^19+(√2+1)^-1-(2√2-3)^0
=(3+2√2)^10*(1-√2)^19+(√2+1)^-1-1
=(√2+1)^20*(1-√2)^19+(√2+1)^-1-1
=(√2+1)*(√2+1)^19*(1-√2)^19+(√2+1)^-1-1
=(√2+1)*[(√2+1)(1-√2)]^19+(√2+1)^-1-1
=(√2+1)*(-1)^19+(√2+1)^-1-1
=-(√2+1)+1/(√2+1)-1
=-(√2+1)+(√2-1)/(√2+1)(√2-1)-1
=-(√2+1)+(√2-1)-1
=-√2-1+√2-1-1
=-3
很简单啊。。主要是凑起来就好了。答案-2√2减1
(3+2√2)^10*(1-√2)^19+1/(√2+1)-(2√2-3)^0 =
(3+2√2)^10*(1-√2)^20/(1-√2)+1/(√2+1)-(2√2-3)^0 =
(3+2√2)^10*(3-2√2)^10/(1-√2)+1/(√2+1)-(2√2-3)^0 =
(1)^10/(1-√2)+1/(√2+1)-(2√2-3)^0 =
-1-√2+√2-1-1= -3
(3+2√2)^10*(1-√2)^19+(√2+1)^(-1)-(2√2-3)^0=(3+2√2)^10*(3-2√2)^10*(1-√2)^(-1)+(√2+1)^(-1)-1=(1-√2)^(-1)+(√2+1)^(-1)-1=-(√2+1)+√2-1-1=-3