若实数x,y满足{x-y+1≥,x>0},则y/(x-1)的取值范围是
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![若实数x,y满足{x-y+1≥,x>0},则y/(x-1)的取值范围是](/uploads/image/z/2521906-34-6.jpg?t=%E8%8B%A5%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B3%7Bx-y%2B1%E2%89%A5%2Cx%3E0%7D%2C%E5%88%99y%2F%28x-1%29%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF)
若实数x,y满足{x-y+1≥,x>0},则y/(x-1)的取值范围是
若实数x,y满足{x-y+1≥,x>0},则y/(x-1)的取值范围是
若实数x,y满足{x-y+1≥,x>0},则y/(x-1)的取值范围是
题目不完整啊.如果是x-y+1>=0的话,那取值范围是R.
如果是
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