已知实数x.y满足ㄧ2x-y+1ㄧ+2(3x-2y+4)^2=0,求代数式1-x-y/x-2y除x^2-y^2/x^2-4xy+4y^2 希望你门看的清楚
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![已知实数x.y满足ㄧ2x-y+1ㄧ+2(3x-2y+4)^2=0,求代数式1-x-y/x-2y除x^2-y^2/x^2-4xy+4y^2 希望你门看的清楚](/uploads/image/z/330697-1-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0x.y%E6%BB%A1%E8%B6%B3%E3%84%A72x-y%2B1%E3%84%A7%2B2%283x-2y%2B4%29%5E2%3D0%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F1-x-y%2Fx-2y%E9%99%A4x%5E2-y%5E2%2Fx%5E2-4xy%2B4y%5E2+%E5%B8%8C%E6%9C%9B%E4%BD%A0%E9%97%A8%E7%9C%8B%E7%9A%84%E6%B8%85%E6%A5%9A)
已知实数x.y满足ㄧ2x-y+1ㄧ+2(3x-2y+4)^2=0,求代数式1-x-y/x-2y除x^2-y^2/x^2-4xy+4y^2 希望你门看的清楚
已知实数x.y满足ㄧ2x-y+1ㄧ+2(3x-2y+4)^2=0,求代数式1-x-y/x-2y除x^2-y^2/x^2-4xy+4y^2 希望你门看的清楚
已知实数x.y满足ㄧ2x-y+1ㄧ+2(3x-2y+4)^2=0,求代数式1-x-y/x-2y除x^2-y^2/x^2-4xy+4y^2 希望你门看的清楚
ㄧ2x-y+1ㄧ+2(3x-2y+4)^2=0
2x-y+1=0
3x-2y+4=0
解方程组得:
x=2,y=5
1-(x-y)/(x-2y)除x^2-y^2/x^2-4xy+4y^2
=1-(x-y)/(x-2y)*(x-2y)^2/(x-y)(x+y)
=1-(x-2y)/(x+y)
=3y/(x+y)
=15/(2+5)
=15/7
我砍不清不过我可以告诉你方法
绝对值+平方=0
就是0或0
所以2x-y-+1=0
3x-25+4=0
再代下
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