y[y-3(x-y)]+y[3y-(y-3x)]=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/17 03:48:53
![y[y-3(x-y)]+y[3y-(y-3x)]=?](/uploads/image/z/3722217-33-7.jpg?t=y%5By-3%28x-y%29%5D%2By%5B3y-%28y-3x%29%5D%3D%3F)
y[y-3(x-y)]+y[3y-(y-3x)]=?
y[y-3(x-y)]+y[3y-(y-3x)]=?
y[y-3(x-y)]+y[3y-(y-3x)]=?
原式
=y(y-3x+3y)+y(3y-y+3x)
=y(4y-3x)+y(2y+3x)
=4y²-3xy+2y²+3xy
=6y²
原式=y(y-3(x-y)+3y-(y-3x))
=y(y-3x+3y+3y-y+3x)
=y(6y)
=6y^2