初一的计算和因式分解帮帮忙5题计算(-2003)×2÷1/2+(-1/3)^-2÷2^-3 2011^2-2010*2012因式分解4X^2-64 -X^2+2X^2-X 化简(3X+2)(3X-2)-5X(X-1)-(2X-1)^2
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![初一的计算和因式分解帮帮忙5题计算(-2003)×2÷1/2+(-1/3)^-2÷2^-3 2011^2-2010*2012因式分解4X^2-64 -X^2+2X^2-X 化简(3X+2)(3X-2)-5X(X-1)-(2X-1)^2](/uploads/image/z/4316143-31-3.jpg?t=%E5%88%9D%E4%B8%80%E7%9A%84%E8%AE%A1%E7%AE%97%E5%92%8C%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E5%B8%AE%E5%B8%AE%E5%BF%995%E9%A2%98%E8%AE%A1%E7%AE%97%EF%BC%88-2003%29%C3%972%C3%B71%2F2%2B%28-1%2F3%29%5E-2%C3%B72%5E-3+2011%5E2-2010%2A2012%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A34X%5E2-64+-X%5E2%2B2X%5E2-X+%E5%8C%96%E7%AE%80%283X%2B2%29%283X-2%29-5X%28X-1%29-%282X-1%29%5E2)
初一的计算和因式分解帮帮忙5题计算(-2003)×2÷1/2+(-1/3)^-2÷2^-3 2011^2-2010*2012因式分解4X^2-64 -X^2+2X^2-X 化简(3X+2)(3X-2)-5X(X-1)-(2X-1)^2
初一的计算和因式分解帮帮忙5题
计算
(-2003)×2÷1/2+(-1/3)^-2÷2^-3 2011^2-2010*2012
因式分解
4X^2-64 -X^2+2X^2-X
化简
(3X+2)(3X-2)-5X(X-1)-(2X-1)^2
初一的计算和因式分解帮帮忙5题计算(-2003)×2÷1/2+(-1/3)^-2÷2^-3 2011^2-2010*2012因式分解4X^2-64 -X^2+2X^2-X 化简(3X+2)(3X-2)-5X(X-1)-(2X-1)^2
(-2003)×2÷(1/2) + (-1/3)^(-2)÷2^(-3)
= -2003×2×2 + [(-3)^2]×(2^3)
= -8012 + 9×8
= -7940
2011^2 - 2010×2012
= 2011^2 - (2011-1)×(2011+1)
= 2011^2 - (2011^2 -1)
= 1
4X^2-64
= 4(X^2 - 16)
= 4(X^2 - 4^2)
= 4(X+4)(X-4)
因式分解的第二题第一项是3次方还是2次方,下面两种分别给出:
-X^3+2X^2-X
= -X(X^2-2X+1)
= -X(X-1)^2
-X^2+2X^2-X
= X^2-X
= X(X-1)
(3X+2)(3X-2)-5X(X-1)-(2X-1)^2
= (3X)^2 - 2^2 - 5X^2 + 5X - [(2X)^2 - 2(2X) + 1]
= 9X^2 - 4 -5X^2 + 5X -4X^2 + 4X - 1
= 9X-5
计算: -7940 1
因式分解:4(X+4)(X-4) X(X-1)
化简;9X-5