6道初三用因式分解法解二元一次方程题 老大们帮帮忙①169(x+3)²-196(x-2)²=0②4x²-5x-7=0③4(x+3)²=9(2x-1)²④3(3-x)²+x(x-3)=0⑤(x+2)²+3(x+2)-4=
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![6道初三用因式分解法解二元一次方程题 老大们帮帮忙①169(x+3)²-196(x-2)²=0②4x²-5x-7=0③4(x+3)²=9(2x-1)²④3(3-x)²+x(x-3)=0⑤(x+2)²+3(x+2)-4=](/uploads/image/z/5197739-59-9.jpg?t=6%E9%81%93%E5%88%9D%E4%B8%89%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%A7%A3%E4%BA%8C%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%E9%A2%98+%E8%80%81%E5%A4%A7%E4%BB%AC%E5%B8%AE%E5%B8%AE%E5%BF%99%E2%91%A0169%EF%BC%88x%EF%BC%8B3%EF%BC%89%26%23178%3B-196%EF%BC%88x-2%EF%BC%89%26%23178%3B%EF%BC%9D0%E2%91%A14x%26%23178%3B-5x-7%EF%BC%9D0%E2%91%A24%EF%BC%88x%EF%BC%8B3%EF%BC%89%26%23178%3B%EF%BC%9D9%EF%BC%882x-1%EF%BC%89%26%23178%3B%E2%91%A33%283-x%29%26%23178%3B%EF%BC%8Bx%EF%BC%88x-3%EF%BC%89%EF%BC%9D0%E2%91%A4%EF%BC%88x%EF%BC%8B2%EF%BC%89%26%23178%3B%EF%BC%8B3%EF%BC%88x%EF%BC%8B2%EF%BC%89-4%EF%BC%9D)
6道初三用因式分解法解二元一次方程题 老大们帮帮忙①169(x+3)²-196(x-2)²=0②4x²-5x-7=0③4(x+3)²=9(2x-1)²④3(3-x)²+x(x-3)=0⑤(x+2)²+3(x+2)-4=
6道初三用因式分解法解二元一次方程题 老大们帮帮忙
①169(x+3)²-196(x-2)²=0
②4x²-5x-7=0
③4(x+3)²=9(2x-1)²
④3(3-x)²+x(x-3)=0
⑤(x+2)²+3(x+2)-4=0
⑥(3x-2)(x-4)+11=0
6道初三用因式分解法解二元一次方程题 老大们帮帮忙①169(x+3)²-196(x-2)²=0②4x²-5x-7=0③4(x+3)²=9(2x-1)²④3(3-x)²+x(x-3)=0⑤(x+2)²+3(x+2)-4=
①169(x+3)²-196(x-2)²=0
[13(x+3)]²-[14(x-2)]²=0
[(13x+39)+(14x-28)][(13x+39)-(14x-28)]=0
(27x+11)(-x+67)=0
x1=-11/27
x2=67
②4x²-3x-7=0
(4x-7)(x+1)=0
x1=7/4
x2=-1
③4(x+3)²=9(2x-1)²
[2(x+3)]²-[3(2x-1)]²=0
[(2x+6)+(6x-3)][(2x+6)-(6x-3)]=0
(8x+3)(-4x+9)=0
x1=-3/8
x2=9/4
④3(3-x)²+x(x-3)=0
3(x-3)²+x(x-3)=0
(x-3)[3(x-3)+x]=0
(x-3)[3x-9+x]=0
(x-3)[4x-9]=0
x1=3
x2=9/4
⑤(x+2)²+3(x+2)-4=0
[(x+2)+4][(x+2)-1]=0
(x+6)(x+1)=0
x1=-6
x2=-1
⑥(3x+2)(x-4)+11=0
3x^2+2x-12x-8+11=0
3x^2-10x+3=0
(3x-1)(x-3)=0
x1=1/3
x2=3